Posted 19 Nov 2010 · Report post Iluzii optice (mai mult sau mai puţin) Atenţie la figuranţi! Share this post Link to post Share on other sites
Posted 20 Nov 2010 · Report post Dintr-un pub de prin Bucuresti... Share this post Link to post Share on other sites
Posted 20 Nov 2010 · Report post ii mai ieftin asa:lol: :lol: iei un logan si-l redenumesti VOLVO(bine ca nu-i FH) Share this post Link to post Share on other sites
Posted 26 Nov 2010 · Report post Sigmund Freud would be proud... Share this post Link to post Share on other sites
Posted 26 Nov 2010 (edited) · Report post Well, they rub her belly, not her p**sy... anyone may, as well, rub the father's stomach, anyway... (and say "how many beers were necessary to trick you into it?") Edited 26 Nov 2010 by Raula Share this post Link to post Share on other sites
Posted 26 Nov 2010 (edited) · Report post it´s not the stomach that did the job. Edited 26 Nov 2010 by LeChuck Share this post Link to post Share on other sites
Posted 26 Nov 2010 (edited) · Report post No, it was the beer in it... ...if you rub it to much, it pops... (I'm talking about the beer, even though so does the stomach) Edited 26 Nov 2010 by Raula Share this post Link to post Share on other sites
Posted 26 Nov 2010 · Report post fie x= femeia (cu proprietatea ca este continuua si derivabila peste tot) si y= barbatul (cu proprietatea ca descreste asimptotic la zero) daca exista z (barbat) , cu proprietatea ca x se imparte exact si la y si la z , atunci exista cel putin un epsilon oricit de mic egal cu limita sirului format din rapoartele lui x cu celelalte numere. daca, insa , x e numar prim , deci nu se imparte exact decit la unu si la el insusi, atunci ecuatia integrala dubla de volum din F(x,y,z) = 0 , are radacini multiple . daca x nu e nici macar numar prim atunci se aplica regula miinii drepte. am expus aceasta demonstratie pentru a intelege si femeile - in sfirsit ! - de ce beau baietii bere. Share this post Link to post Share on other sites
Posted 27 Nov 2010 (edited) · Report post sa se demonstreze ca sirul rapoartelor xn=f(n) este convergent pt. n -> +inf.! Edited 27 Nov 2010 by LeChuck Share this post Link to post Share on other sites
Posted 27 Nov 2010 · Report post Pai... e divergent deoarece limita n -> inf din f(n) -> inf Share this post Link to post Share on other sites
Posted 29 Dec 2010 · Report post http://www.neuronu.ro/funny/top-10-%E2%80%93-romanian-stil-4/ Share this post Link to post Share on other sites
Posted 3 Feb 2011 · Report post Nu parca pe locul lui!!.. Share this post Link to post Share on other sites
Posted 4 Feb 2011 · Report post Pe uverturii...(Bucuresti, sector 6) V-am rugat sa nu mai folositi "K" :lol: Share this post Link to post Share on other sites
Posted 10 Feb 2011 · Report post spirit de observatie.. Share this post Link to post Share on other sites
Posted 16 Feb 2011 · Report post Au vrut sa scrie pensii (cred) Share this post Link to post Share on other sites
Posted 16 Feb 2011 · Report post sau,poate, nu e nici o greseala.... ? Share this post Link to post Share on other sites
Posted 16 Feb 2011 · Report post Doamne, cat am putut sa râd... Share this post Link to post Share on other sites
Posted 10 Sep 2011 · Report post Una roz bucata volvo ! Share this post Link to post Share on other sites
Posted 22 Sep 2011 · Report post http://blogdeprost.b...j-ingenios.html Share this post Link to post Share on other sites
